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7m^2+14m-76=0
a = 7; b = 14; c = -76;
Δ = b2-4ac
Δ = 142-4·7·(-76)
Δ = 2324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2324}=\sqrt{4*581}=\sqrt{4}*\sqrt{581}=2\sqrt{581}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{581}}{2*7}=\frac{-14-2\sqrt{581}}{14} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{581}}{2*7}=\frac{-14+2\sqrt{581}}{14} $
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